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The equation is y = 2x2 - 3x.
You are watching: Y=-2x-2
Here x2coefficient is 2, because that perfect square do x2coefficient 1 by factor out 2.
y = 2(x2 - 3/2 x )
To readjust the expression (x2 - 3/2 x ) into a perfect square trinomialadd (half thexcoefficient)²to every side that the expression.
Herexcoefficient = 3/2. So, (half thexcoefficient)² = (3/4)2= 9/16.
Add 2(9/16) = 9/8 to each side of the equation.
y + 9/8 = 2(x2 - 3/2 x + 9/16)
y + 9/8 = 2(x - 3/4)2
y = 2(x - 3/4)2 - 9/8
The above equation represent the standard type of the equation the parabola.
The standard kind of the parabola with vertex (h, k) and axis of the opposite x = h is y = a(x - h)2 + k.
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The vertex kind of the equation that parabola is y = 2(x - 3/4)2 - 9/8 and also Vertex : (h, k ) = (3/4, - 9/8).answeredMar 30, 2014by steveScholareditedMar 30, 2014by steve please log in or register to add a comment. related questionsh(x)=3x^2-6x-9 in peak formaskedFeb 21, 2014in ALGEBRA 2by paytonApprenticevertex-of-a-parabola compose quadratic role in standard (vertex) form.?askedNov 18, 2014in PRECALCULUSby anonymousvertex-of-a-parabola uncover the focus, vertex, directrix, domain, range, and graph the parabola of y= 3/2x^2askedApr 9, 2014in ALGEBRA 2by anonymousvertex-of-a-parabolagraphing-parabolasvertex-focus-and-directrix-in-paraboladirectrixparabolas create the equation that a parabola with a vertex at (-5, 2) and a directrix y = -1askedFeb 21, 2014in GEOMETRYby dkinzApprenticevertex-of-a-parabola crest of y=3x^2+6x-2askedFeb 21, 2014in GEOMETRYby harvy0496Apprenticevertex-of-a-parabola find the crest of the parabola y=2x^2-10x+1askedFeb 21, 2014in GEOMETRYby homeworkhelpMentorvertex-of-a-parabola what"s the axis of symetry, vertex, and graph y=2x^2+6x-1askedDec 5, 2013in GEOMETRYby lindaScholaraxis-of-symmetryvertex-of-a-parabola create an equation that a parabola with a vertex at ( 2,-2), opened to the right, and going through the allude ( 3, -10)askedAug 7, 2014in ALGEBRA 2by hana_24Novicevertex-of-a-parabolaparabola-notcentered-at-origin discover the crest of the parabola f(X)=3x^2+5x-2askedFeb 21, 2014in ALGEBRA 2by rockstarApprenticevertex-of-a-parabola what is the crest of -5x^2-3x-2?askedFeb 21, 2014in ALGEBRA 2by lindaScholarvertex-of-a-parabola discover the vertex, focus and also directrix the the parabola and also sketc y^2 + 2y + 12x + 30 = 0askedMay 24, 2014in ALGEBRA 2by anonymousvertex-of-a-paraboladirectrix find the crest y+-5(x+2)^2+5askedMar 10, 2014in ALGEBRA 2by andrewScholarvertex-of-a-parabolay-intercept f(x)=(x-1)^2-2 discover the vertex, the y intercept and also x intercept if anyaskedFeb 21, 2014in ALGEBRA 2by angel12Scholarvertex-of-a-parabolax-intercepty-intercept f(x)= -X^2-2x+1 find the roots making use of the quadratic formula label the axis that symmetry and vertexaskedMar 12, 2014in GEOMETRYby lindaScholargraphing-quadratic-equationaxis-of-symmetryvertex-of-a-parabola 2x^2+6x+5y+10=0 need vertex, directrex and also focus,askedFeb 21, 2014in GEOMETRYby futaiScholarvertex-of-a-paraboladirectrixfocusparabolas uncover the peak & graph g(x)=2x^2-x-3askedFeb 21, 2014in GEOMETRYby abstain12Apprenticevertex-of-a-parabolagraph-of-the-equaion what is the axis the summetry and vertex and also yint and also xint that -x^2+2x+15askedDec 5, 2013in GEOMETRYby andrewScholaraxis-of-symmetryvertex-of-a-parabola discover b and c so that y=5x^2+bx+c and has a vertex of (8.-10)askedMar 5, 2014in GEOMETRYby abstain12Apprenticevertex-of-a-parabola because that the parabola, x^2+6 x-12 y-51 = 0 uncover the vertex,focus and the directrixaskedFeb 21, 2014in GEOMETRYby skylarApprenticevertex-of-a-parabolaparabolasfocusdirectrix WHAT IS THE vertex OF Y=5X^2+10X+24?askedFeb 21, 2014in GEOMETRYby mathgirlApprenticevertex-of-a-parabola