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The various other two distinct factoring recipe you"ll have to memorize room very comparable to one another; they"re the formulas because that factoring the sums and also the differences of cubes. Here are the 2 formulas:

You"ll discover in more advanced classes exactly how they came up v these formulas. Because that now, just memorize them.

You are watching: (a+b)(a^2-ab+b^2)

To assist with the memorization, an initial notice the the *terms* in every of the 2 factorization recipe are precisely the same. Then notice that each formula has actually only one "minus" sign. The distinction between the two formulas is in the ar of that one "minus" sign:

For the *difference* the cubes, the "minus" authorize goes in the linear factor, *a* – *b*; for the *sum* of cubes, the "minus" authorize goes in the quadratic factor, *a*2 – *ab* + *b*2.

Some civilization use the mnemonic "**SOAP**" to assist keep track of the signs; the letter stand because that the linear factor having the "same" sign as the sign in the center of the initial expression, climate the quadratic factor starting with the "opposite" authorize from what remained in the initial expression, and finally the 2nd sign inside the quadratic variable is "always positive".

Whatever technique best helps you keep these formulas straight, usage it, since you need to not assume that you"ll be provided these formulas on the test. You must expect to require to understand them.

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Note: The quadratic section of each cube formula *does not factor*, therefore don"t rubbish time attempting to factor it. Yes, *a*2 – 2*ab* + *b*2 and*a*2+ 2*ab* + *b*2 factor, yet that"s since of the 2"s on their middle terms. This sum- and difference-of-cubes formulas" quadratic terms *do not have* that "2", and also thus *cannot* factor.

When you"re provided a pair the cubes come factor, carefully apply the ideal rule. By "carefully", I average "using clip to store track of everything, specifically the negative signs". Here are some typical problems:

variable*x*3 – 8

This is identical to *x*3 – 23. V the "minus" authorize in the middle, this is a distinction of cubes. To carry out the factoring, I"ll be plugging *x* and also 2 right into the difference-of-cubes formula. Doing so, ns get: